Print Options

Card layout:

← Back to notecard set|Easy Notecards home page

Instructions for Side by Side Printing
  1. Print the notecards
  2. Fold each page in half along the solid vertical line
  3. Cut out the notecards by cutting along each horizontal dotted line
  4. Optional: Glue, tape or staple the ends of each notecard together
  1. Verify Front of pages is selected for Viewing and print the front of the notecards
  2. Select Back of pages for Viewing and print the back of the notecards
    NOTE: Since the back of the pages are printed in reverse order (last page is printed first), keep the pages in the same order as they were after Step 1. Also, be sure to feed the pages in the same direction as you did in Step 1.
  3. Cut out the notecards by cutting along each horizontal and vertical dotted line
Print these notecards...Print as a list

95 notecards = 24 pages (4 cards per page)

Viewing:

Chemistry Chapter 9 Final Exam

front 1

According to valence bond theory, which orbitals overlap in the formation of the bond in Cl2?

4p on Cl and 4p on Cl

3p on Cl and 3p on Cl

sp on Cl and sp on Cl

3s on Cl and 3s on Cl

2p on Cl and 2p on Cl

back 1

Answer: 3p on Cl and 3p on Cl

front 2

The molecular geometry of the IF5 molecule is ________, and this molecule is ________.

trigonal bipyramidal, polar

trigonal bipyramidal, nonpolar

trigonal planar, polar

square pyramidal, polar

square pyramidal, nonpolar

back 2

Answer: square pyramidal, polar

front 3

For molecules with only one central atom, how many lone pairs on the central atom guarantees molecular polarity?

1

2

1 or 2

3

1 or 3

back 3

Answer: 1

front 4

ClF3 has ""T-shaped"" geometry. There is/are ________ non-bonding domain(s) in this molecule.

4

2

3

1

0

back 4

Answer: 2

front 5

Molecular Orbital theory correctly predicts diamagnetism of fluorine gas, F2. This is because ________.

the bond order in F2 can be shown to be equal to 1.

there are more electrons in the bonding orbitals than in the antibonding orbitals.

all electrons in the MO electron configuration of F2 are paired.

the energy of the π2pMOs is higher than that of the σ2p MO.

the F—F bond enthalpy is very low.

back 5

Answer:

all electrons in the MO electron configuration of F2 are paired.

front 6

The hybridizations of bromine in BrF5 and of arsenic in AsF5 are ________ and ________, respectively.

sp3, sp3dsp3d,

sp3d2sp3d,

sp3 sp3d2,

sp3d2, sp3d

sp3dsp3d2, sp3d2

back 6

Answer: sp3d2, sp3d

front 7

The hybrid orbital set used by the central atom in SO3 is ________.

sp

sp2

sp3

sp3d

sp3d2

back 7

Answer: sp2

front 8

The electron-domain geometry and molecular geometry of the nitrite ion are ________ and ________, respectively.

trigonal bipyramidal, trigonal planar

tetrahedral, trigonal pyramidal

trigonal bipyramidal,T-shaped

trigonal planar, bent

T-shaped, trigonal planar

back 8

Answer: trigonal planar, bent

front 9

________ hybrid orbitals are used for bonding by Xe in the XeF4 molecule.

sp2

sp3

sp3d

sp3d2

sp

back 9

Answer: sp3d2

front 10

n a typical multiple bond, the σ bond results from overlap of ________ orbitals and the π bond(s) result from overlap of ________ orbitals.

hybrid, atomic

hybrid, hybrid

atomic, hybrid

hybrid, hybrid or atomic

hybrid or atomic, hybrid or atomic

back 10

Answer: hybrid, atomic

front 11

Of the molecules below, only ________ is nonpolar.

PF3

Br2S

TeCl2

HCl

BeH2

back 11

Answer: BeH2

front 12

Based on molecular orbital theory, the bond order of the H—H bond in the H2+ ion is ________.

0

1/2

1

3/2

2

back 12

Answer:

1/2

front 13

Based on molecular orbital theory, the only molecule in the list below that has unpaired electrons is ________.

C2

N2

F2

O2

Li2

back 13

Answer: O2

front 14

n comparing the same two atoms bonded together, the ________ the bond order, the ________ the bond length, and the ________ the bond energy.

smaller, longer, smaller

greater, greater, greater

greater, longer, greater

greater, shorter, smaller

smaller, greater, greater

back 14

Answer:

smaller, longer, smaller

front 15

According to valence bond theory, which orbitals overlap in the formation of the bond in Br2?

3s

3p

4s

4p

3d

back 15

Answer: 4p

front 16

The N-N bond in HNNH consists of ________.

one σ bond and one π bond

one σ bond and two π bonds

two σ bonds and one π bond

two σ bonds and two π bonds

one σ bond and no π bonds

back 16

Answer:

one σ bond and one π bond

front 17

In counting the electron domains around the central atom in VSEPR theory, a ________ is not included.

nonbonding pair of electrons

single covalent bond core level electron pair

double covalent bond

triple covalent bond

back 17

Answer: core level electron pair

front 18

he electron-domain geometry and molecular geometry of iodine trichloride are ________ and ________, respectively.

trigonal bipyramidal, trigonal planar

tetrahedral, trigonal pyramidal

trigonal bipyramidal, T-shaped

octahedral, trigonal planar

T-shaped, trigonal planar

back 18

Answer: trigonal bipyramidal, T-shaped

front 19

The angles between sp2 orbitals are ________.

45°

180°

90°

109.5°

120°

back 19

Answer: 120°

front 20

There are ________ σ bonds and ________ π bonds in H3C–CH2–CH=CH–CH2–C≡CH.

14, 2

10, 3

12, 2

13, 2

16, 3

back 20

Answer:

16, 3

front 21

According to valence bond theory, which orbitals overlap in the formation of the bond in Br2?

3s

3p

4s

4p

3d

back 21

Answer: 4p

front 22

Based on molecular orbital theory, the bond orders of the H—H bonds in H2, H2+, and H2- are ________, respectively

1, 0, and 0

1, 1/2, and 0

1, 0, and 1/2

1, 1/2, and 1/2

1, 2, and 0

back 22

Answer:

1, 1/2, and 1/2

front 23

Of the molecules below, only ________ is nonpolar.

PF3

Br2S

TeCl2

HCl

BeH2

back 23

Answer: BeH2

front 24

For a molecule with the formula AB2, the molecular shape is ________.

linear or bent

linear or trigonal planar

linear or T-shaped

T-shaped

trigonal planar

back 24

Answer: linear or bent

front 25

The molecular geometry of the CS2 molecule is ________.

linear

bent

tetrahedral

trigonal planar

T-shaped

back 25

Answer: linear

front 26

A typical double bond ________.

is stronger and shorter than a single bond

consists of one σ bond and one π bond

imparts rigidity to a molecule

consists of two shared electron pairs

All of the above answers are correct.

back 26

Answer:

All of the above answers are correct.

front 27

When three atomic orbitals are mixed to form hybrid orbitals, how many hybrid orbitals are formed?

six

four

five

three

one

back 27

Answer: three

front 28

The hybrid orbitals used for bonding by Xe in the unstable XeF2 molecule are ________ orbitals.

sp2

sp3

sp3d

sp3d2

sp

back 28

Answer: sp3d

front 29

An antibonding π orbital contains a maximum of ________ electrons.

1

2

4

6

8

back 29

Answer:

2

front 30

An antibonding MO ________ the corresponding bonding MO.

is always lower in energy than

can accommodate more electrons than

can accommodate fewer electrons than is always higher in energy than

is always degenerate with

back 30

Answer: is always higher in energy than

front 31

ClF3 has ""T-shaped"" geometry. There is/are ________ non-bonding domain(s) in this molecule.

4

2

3

1

0

back 31

Answer: 2

front 32

In order to exhibit delocalized π bonding, a molecule must have ________.

at least two π bonds

at least two resonance structures

at least three σ bonds

at least four atoms

trigonal planar electron domain geometry

back 32

Answer:

at least two resonance structures

front 33

According to MO theory, overlap of two p atomic orbitals produces ________.

two bonding molecular orbitals one bonding molecular orbital and one antibonding molecular orbital

two bonding molecular orbitals and two antibonding molecular orbitals

two bonding molecular orbitals and one antibonding molecular orbital

three bonding molecular orbitals and three antibonding molecular orbitals

back 33

Answer: one bonding molecular orbital and one antibonding molecular orbital

front 34

The central atom in a certain molecule has 2 nonbonded electron pairs and 4 bonded electron pairs in its valence shell. The molecular geometry of this molecule is ________.

seesaw

square planar

linear

trigonal bipyramidal

T-shaped

back 34

Answer:

square planar

front 35

The electron-domain geometry of a sulfur-centered compound is trigonal bipyramidal. The hybridization of the central sulfur atom is ________.

sp

sp2

sp3

sp3d

sp3d2

back 35

Answer: sp3d

front 36

According to valence bond theory, which orbitals overlap in the formation of the bond in Cl2?

4p on Cl and 4p on Cl

3p on Cl and 3p on Cl

sp on Cl and sp on Cl

3s on Cl and 3s on Cl

2p on Cl and 2p on Cl

back 36

Answer: 3p on Cl and 3p on Cl

front 37

he blending of one s atomic orbital and one p atomic orbital produces ________.

two sp hybrid orbitals

two sp2 hybrid orbitals

two sp3 hybrid orbitals

three sp hybrid orbitals

three sp2 hybrid orbitals

back 37

Answer: two sp hybrid orbitals

front 38

The electron-domain geometry of ________ is tetrahedral.

CBr4

PH3

CCl2

Br2

Xe

F4

all of the above except XeF4

back 38

Answer: all of the above except XeF4

front 39

The molecular geometry of the BeCl2 molecule is ________, and this molecule is ________.

bent, nonpolar

linear, polar

bent, polar

seesaw, polar

linear, nonpolar

back 39

Answer: linear, nonpolar

front 40

n order to produce sp2 hybrid orbitals, ________ s atomic orbital(s) and ________ p atomic orbital(s) must be mixed.

one, two

one, three

one, one

two, two

two, three

back 40

Answer: one, two

front 41

The electron-domain geometry and the molecular geometry of a molecule of the general formula ABn are ________.

never the same

always the same

sometimes the same

not related

mirror images of one another

back 41

Answer: sometimes the same

front 42

For a molecule with the formula AB2, the molecular shape is ________.

linear or bent

linear or trigonal planar

linear or T-shaped

T-shaped

trigonal planar

back 42

Answer: linear or bent

front 43

Which of the following molecules or ions will exhibit delocalized bonding?

NO2- NH4+ N3-

NH4+ and N3-

NO2- only

NO2-, NH4+, and N3-

N3- only

NO2- and N3-

back 43

Answer: NO2- only

front 44

The hybridizations of nitrogen in NF3 and NH3 are ________ and ________, respectively.

sp2, sp2

sp, sp3

sp3, sp

sp3, sp3

sp2, sp3

back 44

Answer: sp3, sp3

front 45

he electron domain and molecular geometry of SO3 are ________.

trigonal bipyramidal, trigonal planar

trigonal planar, bent

trigonal bipyramidal, T-shaped

trigonal planar, trigonal planar

octahedral, seesaw

back 45

Answer: trigonal planar, trigonal planar

front 46

The central Xe atom in the XeF4 molecule has ________ unbonded electron pair(s) and ________ bonded electron pair(s) in its valence shell.

1, 4

2, 4

4, 0

4, 1

4, 2

back 46

Answer: 2, 4

front 47

The more effectively two atomic orbitals overlap, ________.

the more bonding MOs will be produced by the combination

the higher will be the energy of the resulting bonding MO and the lower will be the energy of the resulting antibonding MO

the higher will be the energies of both bonding and antibonding MOs that result

the fewer antibonding MOs will be produced by the combination

the lower will be the energy of the resulting bonding MO and the higher will be the energy of the resulting antibonding MO

back 47

Answer:

the lower will be the energy of the resulting bonding MO and the higher will be the energy of the resulting antibonding MO

front 48

Using the VSEPR model, the electron-domain geometry of the central atom in ClF3 is ________.

linear

trigonal planar

tetrahedral

trigonal bipyramidal

octahedral

back 48

Answer: trigonal bipyramidal

front 49

he hybridization of the carbon atom in carbon dioxide is ________.

sp

sp2

sp3

sp3d

sp3d2

back 49

Answer: sp

front 50

Of the following species, ________ will have bond angles of 120°.

PH3

ClF3

NCl3

BCl3

All of these will have bond angles of 120°.

back 50

Answer: BCl3

front 51

he hybridization scheme for BeF2 is ________.

sp

sp2

sp3

sp3d

sp3d2

back 51

Answer: sp

front 52

Using the VSEPR model, the molecular geometry of the central atom in PCl3 is ________.

linear

trigonal planar

tetrahedral

bent

trigonal pyramidal

back 52

Answer: trigonal pyramidal

front 53

PCl5 has ________ electron domains and a ________ molecular arrangement.

6, trigonal bipyramidal

6, tetrahedral

5, square pyramidal

5, trigonal bipyramidal

6, seesaw

back 53

Answer: 5, trigonal bipyramidal

front 54

The hybridization of carbon in the H—C ≡ N: molecule is ________.

sp2

s2p

s3p

sp

sp3

back 54

Answer:

sp

front 55

n comparing the same two atoms bonded together, the ________ the bond order, the ________ the bond length, and the ________ the bond energy.

smaller, longer, smaller

greater, greater, greater

greater, longer, greater

greater, shorter, smaller

smaller, greater, greater

back 55

Answer:

smaller, longer, smaller

front 56

Of the following molecules, only ________ is polar.

BeCl2

BF3

CBr4

SiH2Cl2

Cl2

back 56

Answer: SiH2Cl2

front 57

In order to exhibit delocalized π bonding, a molecule must have ________.

at least two π bonds

at least two resonance structures

at least three σ bonds

at least four atoms

trigonal planar electron domain geometry

back 57

Answer:

at least two resonance structures

front 58

The bond order of a homonuclear diatomic molecule can be decreased by ________.

removing electrons from a bonding MO or adding electrons to an antibonding MO

adding electrons to a bonding MO or removing electrons from an antibonding MO

adding electrons to any MO

removing electrons from any MO

The bond order of a homonuclear diatomic molecule cannot be decreased by any means.

back 58

Answer:

removing electrons from a bonding MO or adding electrons to an antibonding MO

front 59

For molecules with only one central atom, how many lone pairs on the central atom guarantees molecular polarity?

1

2

1 or 2

3

1 or 3

back 59

Answer: 1

front 60

f the following, the central atom is sp3d2 hybridized only in ________.

PCl5

XeF4

PH3

Br3-

BeF2

back 60

Answer:

XeF4

front 61

The electron-domain geometry and the molecular geometry of a molecule of the general formula ABn will always be the same if ________.

there are no lone pairs on the central atom

there is more than one central atom

n is greater than four

n is less than four

the octet rule is obeyed

back 61

Answer:

there are no lone pairs on the central atom

front 62

The more effectively two atomic orbitals overlap, ________.

the more bonding MOs will be produced by the combination

the higher will be the energy of the resulting bonding MO and the lower will be the energy of the resulting antibonding MO

the higher will be the energies of both bonding and antibonding MOs that result

the fewer antibonding MOs will be produced by the combination

the lower will be the energy of the resulting bonding MO and the higher will be the energy of the resulting antibonding MO

back 62

Answer: the lower will be the energy of the resulting bonding MO and the higher will be the energy of the resulting antibonding MO

front 63

according to valence bond theory, which orbitals overlap in the formation of the bond in HCl?

1s on H and 2p on Cl

2s on H and 3p on Cl

1s on H and 3s on Cl

1s on H and 3p on Cl

1s on H and 4p on Cl

back 63

Answer: 1s on H and 3p on Cl

front 64

In a typical multiple bond, the σ bond results from overlap of ________ orbitals and the π bond(s) result from overlap of ________ orbitals.

hybrid, atomic

hybrid, hybrid

atomic, hybrid

hybrid, hybrid or atomic

hybrid or atomic, hybrid or atomic

back 64

Answer:

hybrid, atomic

front 65

Of the following molecules, only ________ is polar.

CCl4

BCl3

NCl3

BeCl2

Cl2

back 65

Answer: NCl3

front 66

The hybrid orbitals used for bonding by the sulfur atom in the SF4 molecule are ________ orbitals.

sp

sp2

sp3

sp3d

sp3d2

back 66

Answer: sp3d

front 67

A molecular orbital can accommodate a maximum of ________ electron(s).

1

2

4

6

12

back 67

Answer: 2

front 68

Using the VSEPR model, the molecular geometry of the central atom in CH4 is ________.

linear

trigonal planar

tetrahedral

bent

trigonal pyramidal

back 68

Answer: tetrahedral

front 69

Based on molecular orbital theory, the bond order of the Be Be bond in the Be2 molecule is ________.

0

1

2

3

4

back 69

Answer: 0

front 70

The more effectively two atomic orbitals overlap, ________.

the more bonding MOs will be produced by the combination

the higher will be the energy of the resulting bonding MO and the lower will be the energy of the resulting antibonding MO

the higher will be the energies of both bonding and antibonding MOs that result

the fewer antibonding MOs will be produced by the combination

the lower will be the energy of the resulting bonding MO and the higher will be the energy of the resulting antibonding MO

back 70

Answer:

the lower will be the energy of the resulting bonding MO and the higher will be the energy of the resulting antibonding MO

front 71

In comparing the same two atoms bonded together, the ________ the bond order, the ________ the bond length, and the ________ the bond energy.

smaller, longer, smaller

greater, greater, greater

greater, longer, greater

greater, shorter, smaller

smaller, greater, greater

back 71

Answer:

smaller, longer, smaller

front 72

________ hybrid orbitals are used for bonding by Xe in the XeF4 molecule.

sp2

sp3

sp3d

sp3d2

sp

back 72

Answer: sp3d2

front 73

The Lewis structure of carbon monoxide is given below. The hybridizations of the carbon and oxygen atoms in carbon monoxide are ________ and ________, respectively.

: C ≡ O :

sp, sp3

sp2, sp3

sp3, sp2

sp, sp

sp2, sp2

back 73

Answer:

sp, sp

front 74

According to MO theory, overlap of two s atomic orbitals produces ________.

one bonding molecular orbital and one hybrid orbital

two bonding molecular orbitals

two bonding molecular orbitals and two antibonding molecular orbitals

two bonding molecular orbitals and one antibonding molecular orbital

one bonding molecular orbital and one antibonding molecular orbital

back 74

Answer: one bonding molecular orbital and one antibonding molecular orbital

front 75

The carbon-carbon σ bond in ethylene, H2C=CH2, results from the overlap of ________.

sp hybrid orbitals

sp3 hybrid orbitals

sp2 hybrid orbitals

s atomic orbitals

p atomic orbitals

back 75

Answer:

sp2 hybrid orbitals

front 76

Using the VSEPR model, the electron-domain geometry of the central atom in O3 is ________.

linear trigonal planar

tetrahedral

trigonal bipyramidal

octahedral

back 76

Answer: trigonal planar

front 77

The molecular geometry of ________ is square planar.

CCl4

XeF4

PH3

XeF2

ICl3

back 77

Answer: XeF4

front 78

Of the molecules below, only ________ is polar.

CO2

CH4

PF5

SnF3

H2

back 78

Answer: SnF3

front 79

The Cl-Si-Cl bond angle in the SiCl2F2 molecule is approximately ________.

90°

109.5°

120°

180°

60°

back 79

Answer: 109.5°

front 80

A typical triple bond ________.

consists of one σ bond and two π bonds

consists of three shared electrons

consists of two σ bonds and one π bond

consists of six shared electron pairs

is longer than a single bond

back 80

Answer:

consists of one σ bond and two π bonds

front 81

There is/are ________ hybridized s atomic orbital(s) in an sp-hybridized carbon atom.

4

0

3

1

2

back 81

Answer: 1

front 82

A triatomic molecule cannot be linear if the hybridization of the central atoms is ________.

sp

sp2

sp3

sp2 or sp3

sp2d or sp3d2

back 82

Answer: sp2 or sp3

front 83

A typical double bond consists of ________.

three sigma bonds

three pi bonds

one sigma and two pi bonds

one sigma and one pi bond

three ionic bonds

back 83

Answer: one sigma and one pi bond

front 84

The electron-domain geometry and the molecular geometry of a molecule of the general formula ABn will always be the same if ________.

there are no lone pairs on the central atom

there is more than one central atom

n is greater than four

n is less than four

the octet rule is obeyed

back 84

Answer: there are no lone pairs on the central atom

front 85

The molecular geometry of the CHF3 molecule is ________, and the molecule is ________.

trigonal pyramidal, polar

tetrahedral, nonpolar

seesaw, nonpolar

tetrahedral, polar

seesaw, polar

back 85

Answer: tetrahedral, polar

front 86

The bond angles in a tetrahedral molecule are ________ degrees.

109.5

120

90

45

<45

back 86

Answer: 109.5

front 87

The molecular geometry of the PHCl2 molecule is ________.

bent

trigonal planar

trigonal pyramidal

tetrahedral

T-shaped

back 87

Answer: trigonal pyramidal

front 88

A triatomic molecule cannot be linear if the hybridization of the central atoms is ________.

sp

sp2

sp3

sp2 or sp3

sp2d or sp3d2

back 88

Answer: sp2 or sp3

front 89

The F-N-F bond angle in the NF3 molecule is slightly less than ________.

90°

109.5°

120°

180°

60°

back 89

Answer: 109.5°

front 90

There is/are ________ hybridized s atomic orbital(s) in an sp-hybridized carbon atom.

4

0

3

1

2

back 90

Answer: 1

front 91

The hybrid orbitals used for bonding by the sulfur atom in the SF4 molecule are ________ orbitals.

sp

sp2

sp3

sp3d

sp3d2

back 91

Answer: sp3d

front 92

The molecular geometry of the BeCl2 molecule is ________, and this molecule is ________.

bent, nonpolar

linear, polar

bent, polar

seesaw, polar

linear, nonpolar

back 92

Answer: linear, nonpolar

front 93

Of the following molecules, only ________ is polar.

BeCl2

BF3

CBr4

SiH2Cl2

Cl2

back 93

Answer: SiH2Cl2

front 94

The F-B-F bond angle in the BF3 molecule is ________.

90°

109.5°

120°

180°

60°

back 94

Answer: 120°

front 95

In order to produce sp2 hybrid orbitals, ________ s atomic orbital(s) and ________ p atomic orbital(s) must be mixed.

one, two

one, three

one, one

two, two

two, three

back 95

Answer: one, two