Geometry Conjectures
C-14 Median Concurrency
The three medians of a triangle are concurrent.
The point of Concurrency is called the centroid.
C-11 Altitude Concurrency
The three altitudes of a triangle are concurrent.
The point of concurrency is called the Orthocenter
C-10 Perpendicular Bisector Concurrent
The three Perpendicular Bisectors are concurrent.
The point of concurrency is called the circumcenter.
C-9: Angle Bisector Concurrency
The three angle bisectors of a
triangle meet at a
point.
-or-
The three angle bisectors of a
triangle are
concurrent.
C-9: Angle Bisector Concurrency
The point of
concurrency is called the incenter
C-16: Center of Gravity
The centroid of a triangle is the
center of gravity of the triangular
region.
C-15: Centroid Conjecture
The centroid divides the median into
2 segments so that the
distance
from the vertex to the centroid is
twice the
distance from the centroid to the midpoint.
Orthocenter Conjectures
The orthocenter of a right triangle is
on the vertex of the
right angle.
Altitudes
The orthocenter of an obtuse
triangle is outside
of the triangle
Orthocenter Conjectures
C-12: Circumcenter Conjecture
The circumcenter is equidistant from
the vertices of a triangle.
Perpendicular Bisector
Other info:
a. The circumcenter is
outside of an obtuse
triangle
b. The circumcenter is on the
midpoint of the
hypotenuse of a right triangle
c. The
circumcenter is the center of the circle that
circumscribes the triangle
C-13: Incenter Conjecture
The incenter is equidistant from the sides of a triangle.
Angle Bisector
Other info:
a. The incenter is the center of the circle that
is
inscribed inside the triangle
b. Don’t forget that the
distance in question is the
shortest distance, perpendicular from
the
incenter to the side of the triangle
Euler Line Conjecture
The circumcenter, centroid and
orthocenter are
collinear.
For an isosceles triangle, the points
of
concurrency all lie on the angle
bisector of the vertex
angle.
For an equilateral triangle, all 4
points of
concurrency are the same
Euler Segment Conjecture
The centroid divides the Euler
Segment into 2 parts so that
the
smaller part is half of the larger part.