What famil(y)ies of the periodic table is/are being investigated in this experiment?

Halogens AND Alkaline earth metals

Use the following chemical equation to answer the following question

X₂ + 2Y ^{1 minus} ----> 2X ^{1 minus} + Y₂

What species is being reduced?

X₂

In solubility test section of the experiment you will be determining the solubility of various alkaline earth salts. What anions will you be using for your solubility test?

SO₄ ^{2 minus}, IO₃ ^minus, C₂O₄ ^{2 minus} and CO₃ ^{2 minus}

In a test tube you add 2 mL of saturated chlorine water (Cl₂) followed by about 1 mL of an organic solvent such as heptane (or cyclohexane). The test tube is shaken and you notice that the heptane layer has a yellow color. To this mixture you then add 1 mL of 0.1 M N a I. After shaking you notice a color change from yellow to purple in the heptane layer. What can you conclude about Cl and I from this experiment?

Information: Cl₂ is pale yellow; I₂ is purple; I ^minus (N a I) and Cl ^minus (N a Cl) are colorless.

Hint: For A₂ + 2 B ^{1 minus} ---> B₂ + 2 A ^{1 minus}

If a reaction occurs, A is more active than B.

If a reaction does not occur, B is more active than A.

Cl is more active than I because Cl₂ reacted with I ^minus to form I₂ and Cl ^minus

Ex.

By sholanejo on Brainly, https://brainly.com/question/15720257

The organic compounds (heptane/cyclohexane) will get dissolve in Cl₂ water forming a yellow colored solution.

When NaI is added into it, the following reaction between NaI and Cl2 takes place;

Cl₂ + NaI ⇒ I₂ + NaCl

In above reaction, oxidation state of Cl is getting reduced from 0 in Cl2 to -1 in NaCl.

Therefore, Cl2 is getting reduced and acting as an oxidizing agent in the reaction. While I⁻ is getting oxidised annd acting as a reducing agent.