When excess H C l is added to the antacid tablet (C a C O3) used in this experiment, what are the products of this reaction?

Select all correct answers.

• CO₂
• MgCl₂
• NaCl
• CaCl₂
• H₂O

• CO₂
• CaCl₂
• H₂O

What is the correct order of the steps for this experiment?

RIGHT

What is the correct order of the steps for this experiment?

WRONG

How will the number of moles of H C l neutralized by the antacid tablet be determined?

• From the number of moles of N a O H added to react with excess H C l
• Multiplying the volume of H C l added by its molarity to get moles of H C l added
• Subtracting the number of moles of H C l neutralized by NaOH from the number of moles of H C l added to dissolve the tablet
• By converting the mass of the tablet to moles and calculating the number of moles of H C l needed from the volume added and molarity from stoichiometry

Subtracting the number of moles of H C l neutralized by NaOH from the number of moles of H C l added to dissolve the tablet

A student performing this experiment weights out 0.6925 grams of an antacid tablet. It is was determined that this tablet contained 0.4800 grams of C a CO₃. What is the percent C a CO₃ of this tablet?

Type your answers without units.

(0.4800 grams CaCO₃ / 0.6925 grams antacid tablet) x 100 = 69.31% CaCO₃

Answer: 69.31

A student performing this experiment weights out 0.6490 grams of an antacid tablet. It is was determined that this tablet contained 0.4470 grams of C a CO₃. What is the percent C a CO₃ of this tablet?

Type your answers without units.

(0.4470 grams CaCO₃ / 0.6490 grams antacid tablet) x 100 = 68.88% CaCO₃

Answer: 68.88