front 1 ) Garrod hypothesized that ʺinborn errors of metabolismʺ such as
alkaptonuria occur because
- A) genes dictate the production of specific enzymes, and
affected individuals have genetic defects that cause them to lack
certain enzymes.
- B) enzymes are made of DNA, and affected
individuals lack DNA polymerase.
- C) many metabolic enzymes
use DNA as a cofactor, and affected individuals have mutations that
prevent their enzymes from interacting efficiently with DNA.
- D) certain metabolic reactions are carried out by ribozymes, and
affected individuals lack key splicing factors.
- E)
metabolic enzymes require vitamin cofactors, and affected
individuals have significant nutritional deficiencies.
| back 1 - A) genes dictate the production of specific enzymes, and
affected individuals have genetic defects that cause them to lack
certain enzymes.
|
front 2 The following questions refer to Figure 17.1, a simple metabolic pathway:
Figure 17.1
2) According to Beadle and Tatumʹs hypothesis, how many genes are
necessary for this pathway?
A) 0 B) 1 C) 2 D) 3
E) It cannot be determined from the pathway. | |
front 3 - A mutation results in a defective enzyme A. Which of the
following would be a consequence of that mutation? A) an
accumulation of A and no production of B and C B) an accumulation of
A and B and no production of C C) an accumulation of B and no
production of A and C D) an accumulation of B and C and no
production of A E) an accumulation of C and no production of A and
B
| back 3 - A) an accumulation of A and no production of B and C
|
front 4 - 4) If A, B, and C are all required for growth, a strain that is
mutant for the gene encoding enzyme A would be able to grow on which
of the following media? A) minimal medium B) minimal medium
supplemented with nutrient ʺAʺ only C) minimal medium supplemented
with nutrient ʺBʺ only D) minimal medium supplemented with nutrient
ʺCʺ only E) minimal medium supplemented with nutrients ʺAʺ and
ʺCʺ
| back 4 - C) minimal medium supplemented with nutrient ʺBʺ only
|
front 5 - If A, B, and C are all required for growth, a strain mutant for
the gene encoding enzyme B would be capable of growing on which of
the following media? A) minimal medium B) minimal medium
supplemented with ʺAʺ only C) minimal medium supplemented with ʺBʺ
only D) minimal medium supplemented with ʺCʺ only E) minimal medium
supplemented with nutrients ʺAʺ and ʺBʺ
| back 5 - D) minimal medium supplemented with ʺCʺ only
|
front 6 - The nitrogenous base adenine is found in all members of which
group? A) proteins, triglycerides, and testosterone B) proteins,
ATP, and DNA C) ATP, RNA, and DNA D) alpha glucose, ATP, and DNA E)
proteins, carbohydrates, and ATP
| |
front 7 - Using RNA as a template for protein synthesis instead of
translating proteins directly from the DNA is advantageous for the
cell because
- A) RNA is much more stable than DNA.
- B) RNA acts as an expendable copy of the genetic material.
- C) only one mRNA molecule can be transcribed from a
single gene, lowering the potential rate of gene expression.
- D) tRNA, rRNA and others are not transcribed.
- E) mRNA molecules are subject to mutation but DNA is not.
| back 7 - B) RNA acts as an expendable copy of the genetic material
|
front 8 - If proteins were composed of only 12 different kinds of amino
acids, what would be the smallest possible codon size in a genetic
system with four different nucleotides? A) 1 B) 2 C) 3 D) 4 E)
12
| |
front 9 - The enzyme polynucleotide phosphorylase randomly assembles
nucleotides into a polynucleotide polymer. You add polynucleotide
phosphorylase to a solution of adenosine triphosphate and guanosine
triphosphate. How many artificial mRNA 3 nucleotide codons would be
possible? A) 3 B) 4 C) 8 D) 16 E) 64
| |
front 10 - A particular triplet of bases in the template strand of DNA is
5ʹ AGT 3ʹ. The corresponding codon for the mRNA transcribed is A) 3ʹ
UCA 5ʹ. B) 3ʹ UGA 5ʹ. C) 5ʹ TCA 3ʹ. D) 3ʹACU 5ʹ. E) either UCA or
TCA, depending on wobble in the first base.
| |
front 11 A possible sequence of nucleotides in the template strand of DNA that
would code for the polypeptide sequence phe-leu-ile-val would be
A) 5ʹ TTG-CTA-CAG-TAG 3ʹ. B) 3ʹ AAC-GAC-GUC-AUA 5ʹ.
C) 5ʹ AUG-CTG-CAG-TAT 3ʹ. D) 3ʹ AAA-AAT-ATA-ACA 5ʹ. E) 3ʹ
AAA-GAA-TAA-CAA 5ʹ. | back 11 E) 3ʹ AAA-GAA-TAA-CAA 5ʹ. |
front 12 - 12) What amino acid sequence will be generated, based on the
following mRNA codon sequence? 5ʹ AUG-UCU-UCG-UUA-UCC-UUG 3ʹ A)
met-arg-glu-arg-glu-arg B) met-glu-arg-arg-gln-leu C)
met-ser-leu-ser-leu-ser D) met-ser-ser-leu-ser-leu E)
met-leu-phe-arg-glu-glu
| back 12 - D) met-ser-ser-leu-ser-leu
|
front 13 - A peptide has the sequence NH2-phe-pro-lys-gly-phe-pro-COOH.
Which of the following sequences in the coding strand of the DNA
could code for this peptide? A) 3ʹ UUU-CCC-AAA-GGG-UUU-CCC B) 3ʹ
AUG-AAA-GGG-TTT-CCC-AAA-GGG C) 5ʹ TTT-CCC-AAA-GGG-TTT-CCC D) 5ʹ
GGG-AAA-TTT-AAA-CCC-ACT-GGG E) 5ʹ ACT-TAC-CAT-AAA-CAT-TAC-UGA
| back 13 - C) 5ʹ TTT-CCC-AAA-GGG-TTT-CCC
|
front 14 - What is the sequence of a peptide based on the following mRNA
sequence? 5ʹ . . . UUUUCUUAUUGUCUU 3ʹ A) leu-cys-tyr-ser-phe B)
cyc-phe-tyr-cys-leu C) phe-leu-ile-met-val D) leu-pro-asp-lys-gly E)
phe-ser-tyr-cys-leu
| |
front 15 - The genetic code is essentially the same for all organisms.
From this, one can logically assume all of the following except A) a
gene from an organism could theoretically be expressed by any other
organism. B) all organisms have a common ancestor. C) DNA was the
first genetic material. D) the same codons in different organisms
usually translate into the same amino acids. E) different organisms
have the same number of different types of amino acids.
| back 15 - C) DNA was the first genetic material.
|
front 16 - The ʺuniversalʺ genetic code is now known to have exceptions.
Evidence for this could be found if which of the following is true?
- A) If UGA, usually a stop codon, is found to code for an
amino acid such as tryptophan (usually coded for by UGG only).
- B) If one stop codon, such as UGA, is found to have a
different effect on translation than another stop codon, such as
UAA.
- C) If prokaryotic organisms are able to
translate a eukaryotic mRNA and produce the same polypeptide.
- D) If several codons are found to translate to the same
amino acid, such as serine.
- E) If a single mRNA
molecule is found to translate to more than one polypeptide when
there are two or more AUG sites.
| back 16 - A) If UGA, usually a stop codon, is found to code for an amino
acid such as tryptophan (usually coded for by UGG only).
|
front 17 - Which of the following nucleotide triplets best represents a
codon? A) a triplet separated spatially from other triplets B) a
triplet that has no corresponding amino acid C) a triplet at the
opposite end of tRNA from the attachment site of the amino acid D) a
triplet in the same reading frame as an upstream AUG E) a sequence
in tRNA at the 3ʹ end
| back 17 - D) a triplet in the same reading frame as an upstream AUG
|
front 18 - Which of the following is true for both prokaryotic and
eukaryotic gene expression? A) After transcription, a 3ʹ poly-A tail
and a 5ʹ cap are added to mRNA. B) Translation of mRNA can begin
before transcription is complete. C) RNA polymerase binds to the
promoter region to begin transcription. D) mRNA is synthesized in
the 3ʹ → 5ʹ direction. E) The mRNA transcript is the exact
complement of the gene from which it was copied.
| back 18 - C) RNA polymerase binds to the promoter region to begin
transcription.
|
front 19 - In which of the following actions does RNA polymerase differ
from DNA polymerase?
- A) RNA polymerase uses RNA as a
template, and DNA polymerase uses a DNA template.
- B)
RNA polymerase binds to single-stranded DNA, and DNA polymerase
binds to double-stranded DNA.
- C) RNA polymerase is
much more accurate than DNA polymerase.
- D) RNA
polymerase can initiate RNA synthesis, but DNA polymerase
requires a primer to initiate DNA synthesis.
- E) RNA
polymerase does not need to separate the two strands of DNA in
order to synthesize an RNA copy, whereas DNA polymerase must
unwind the double helix before it can replicate the DNA.
| back 19 - D) RNA polymerase can initiate RNA synthesis, but DNA
polymerase requires a primer to initiate DNA synthesis.
|
front 20 - Which of the following statements best describes the
termination of transcription in prokaryotes?
- A) RNA
polymerase transcribes through the polyadenylation signal,
causing proteins to associate with the transcript and cut it
free from the polymerase.
- B) RNA polymerase
transcribes through the terminator sequence, causing the
polymerase to fall off the DNA and release the transcript.
- C) RNA polymerase transcribes through an intron, and the
snRNPs cause the polymerase to let go of the transcript.
- D) Once transcription has initiated, RNA polymerase
transcribes until it reaches the end of the chromosome.
- E) RNA polymerase transcribes through a stop codon, causing
the polymerase to stop advancing through the gene and release
the mRNA.
| back 20 - B) RNA polymerase transcribes through the terminator sequence,
causing the polymerase to fall off the DNA and release the
transcript.
|
front 21 - RNA polymerase moves in which direction along the DNA? A) 3ʹ →
5ʹ along the template strand B) 3ʹ → 5ʹ along the coding (sense)
strand C) 5ʹ → 3ʹ along the template strand D) 3ʹ → 5ʹ along the
coding strand E) 5ʹ → 3ʹ along the double-stranded DNA
| back 21 - A) 3ʹ → 5ʹ along the template strand
|
front 22 - RNA polymerase in a prokaryote is composed of several subunits.
Most of these subunits are the same for the transcription of any
gene, but one, known as sigma, varies considerably. Which of the
following is the most probable advantage for the organism of such
sigma switching?
- A) It might allow the transcription
process to vary from one cell to another.
- B) It might
allow the polymerase to recognize different promoters under
certain environmental conditions.
- C) It could allow
the polymerase to react differently to each stop codon.
- D) It could allow ribosomal subunits to assemble at faster
rates.
- E) It could alter the rate of translation and
of exon splicing.
| back 22 - B) It might allow the polymerase to recognize different
promoters under certain environmental conditions.
|
front 23 - Which of these is the function of a poly (A) signal sequence?
- A) It adds the poly (A) tail to the 3ʹ end of the mRNA.
- B) It codes for a sequence in eukaryotic transcripts
that signals enzymatic cleavage ~10 —35 nucleotides away.
- C) It allows the 3ʹ end of the mRNA to attach to the
ribosome.
- D) It is a sequence that codes for the
hydrolysis of the RNA polymerase.
- E) It adds a
7-methylguanosine cap to the 3ʹ end of the mRNA.
| back 23 - B) It codes for a sequence in eukaryotic transcripts that
signals enzymatic cleavage ~10 —35 nucleotides away.
|
front 24 - 24) In eukaryotes there are several different types of RNA
polymerase. Which type is involved in transcription of mRNA for a
globin protein? A) ligase B) RNA polymerase I C) RNA polymerase II
D) RNA polymerase III E) primase
| |
front 25 - Transcription in eukaryotes requires which of the following in
addition to RNA polymerase? A) the protein product of the promoter
B) start and stop codons C) ribosomes and tRNA D) several
transcription factors (TFs) E) aminoacyl synthetase
| back 25 - D) several transcription factors (TFs)
|
front 26 - A part of the promoter, called the TATA box, is said to be
highly conserved in evolution. Which might this illustrate? A) The
sequence evolves very rapidly. B) The sequence does not mutate. C)
Any mutation in the sequence is selected against. D) The sequence is
found in many but not all promoters. E) The sequence is transcribed
at the start of every gene.
| back 26 - C) Any mutation in the sequence is selected against.
|
front 27 - The TATA sequence is found only several nucleotides away from
the start site of transcription. This most probably relates to which
of the following? A) the number of hydrogen bonds between A and T in
DNA B) the triplet nature of the codon C) the ability of this
sequence to bind to the start site D) the supercoiling of the DNA
near the start site E) the 3-dimensional shape of a DNA
molecule
| back 27 - A) the number of hydrogen bonds between A and T in DNA
|
front 28 - Which of the following help(s) to stabilize mRNA by inhibiting
its degradation? A) TATA box B) spliceosomes C) 5ʹ cap and poly (A)
tail D) introns E) RNA polymerase
| back 28 - C) 5ʹ cap and poly (A) tail
|
front 29 - 29) What is a ribozyme?
- A) an enzyme that uses RNA as
a substrate
- B) an RNA with enzymatic activity
- C) an enzyme that catalyzes the association between the
large and small ribosomal subunits
- D) an enzyme that
synthesizes RNA as part of the transcription process
-
E) an enzyme that synthesizes RNA primers during DNA replication
| back 29 - B) an RNA with enzymatic activity
|
front 30 - What are the coding segments of a stretch of eukaryotic DNA
called? A) introns B) exons C) codons D) replicons E)
transposons
| |
front 31 - A transcription unit that is 8,000 nucleotides long may use
1,200 nucleotides to make a protein consisting of approximately 400
amino acids. This is best explained by the fact that A) many
noncoding stretches of nucleotides are present in mRNA. B) there is
redundancy and ambiguity in the genetic code. C) many nucleotides
are needed to code for each amino acid. D) nucleotides break off and
are lost during the transcription process. E) there are termination
exons near the beginning of mRNA.
| back 31 - A) many noncoding stretches of nucleotides are present in
mRNA.
|
front 32 - Once transcribed, eukaryotic mRNA typically undergoes
substantial alteration that includes A) union with ribosomes. B)
fusion into circular forms known as plasmids. C) linkage to histone
molecules. D) excision of introns. E) fusion with other newly
transcribed mRNA.
| |
front 33 - Introns are significant to biological evolution because A)
their presence allows exons to be shuffled. B) they protect the mRNA
from degeneration. C) they are translated into essential amino
acids. D) they maintain the genetic code by preventing incorrect DNA
base pairings. E) they correct enzymatic alterations of DNA
bases.
| back 33 - A) their presence allows exons to be shuffled.
|
front 34 - A mutation in which of the following parts of a gene is likely
to be most damaging to a cell? A) intron B) exon C) 5ʹ UTR D) 3ʹ UTR
E) All would be equally damaging.
| |
front 35 - Which of the following is (are) true of snRNPs? A) They are
made up of both DNA and RNA. B) They bind to splice sites at each
end of the exon. C) They join together to form a large structure
called the spliceosome. D) They act only in the cytosol. E) They
attach introns to exons in the correct order.
| back 35 - C) They join together to form a large structure called the
spliceosome.
|
front 36 - During splicing, which molecular component of the spliceosome
catalyzes the excision reaction? A) protein B) DNA C) RNA D) lipid
E) sugar
| |
front 37 - Alternative RNA splicing A) is a mechanism for increasing the
rate of transcription. B) can allow the production of proteins of
different sizes from a single mRNA. C) can allow the production of
similar proteins from different RNAs. D) increases the rate of
transcription. E) is due to the presence or absence of particular
snRNPs.
| back 37 - B) can allow the production of proteins of different sizes from
a single mRNA.
|
front 38 - In the structural organization of many eukaryotic genes,
individual exons may be related to which of the following? A) the
sequence of the intron that immediately precedes each exon B) the
number of polypeptides making up the functional protein C) the
various domains of the polypeptide product D) the number of
restriction enzyme cutting sites E) the number of start sites for
transcription
| back 38 - C) the various domains of the polypeptide product
|
front 39 - Each eukaryotic mRNA, even after post-transcriptional
modification, includes 5ʹ and 3ʹ UTRs. Which are these? A) the cap
and tail at each end of the mRNA B) the untranslated regions at
either end of the coding sequence C) the U attachment sites for the
tRNAs D) the U translation sites that signal the beginning of
translation E) the U — A pairs that are found in high frequency at
the ends
| back 39 - B) the untranslated regions at either end of the coding
sequence
|
front 40 - In an experimental situation, a student researcher inserts an
mRNA molecule into a eukaryotic cell after he has removed its 5ʹ cap
and poly(A) tail. Which of the following would you expect him to
find? A) The mRNA could not exit the nucleus to be translated. B)
The cell recognizes the absence of the tail and polyadenylates the
mRNA. C) The molecule is digested by restriction enzymes in the
nucleus. D) The molecule is digested by exonucleases since it is no
longer protected at the 5ʹ end. E) The molecule attaches to a
ribosome and is translated, but more slowly.
| back 40 - D) The molecule is digested by exonucleases since it is no
longer protected at the 5ʹ end.
|
front 41 - A particular triplet of bases in the coding sequence of DNA is
AAA. The anticodon on the tRNA that binds the mRNA codon is A) TTT.
B) UUA. C) UUU. D) AAA. E) either UAA or TAA, depending on first
base wobble.
| |
front 42 - Accuracy in the translation of mRNA into the primary structure
of a polypeptide depends on specificity in the A) binding of
ribosomes to mRNA. B) shape of the A and P sites of ribosomes. C)
bonding of the anticodon to the codon. D) attachment of amino acids
to tRNAs. E) both C and D
| |
front 43 - A part of an mRNA molecule with the following sequence is
being read by a ribosome: 5ʹ CCG-ACG 3ʹ (mRNA). The following
charged transfer RNA molecules (with their anticodons shown in the
3ʹ to 5ʹ direction) are available. Two of them can correctly match
the mRNA so that a dipeptide can form.
tRNA Anticodon Amino Acid
GGC Proline
CGU Alanine
UGC Threonine
CCG Glycine
ACG Cysteine
CGG Alanine
The dipeptide that will form will be A) cysteine-alanine.
B) proline-threonine. C) glycine-cysteine. D) alanine-alanine.
E) threonine-glycine. | |
front 44 What type of bonding is responsible for maintaining the shape of the
tRNA molecule? A) covalent bonding between sulfur atoms
B) ionic bonding between phosphates C) hydrogen bonding
between base pairs D) van der Waals interactions between
hydrogen atoms
E) peptide bonding between amino acids | back 44 C) hydrogen bonding between base pairs |
front 45 Figure 17.4 represents tRNA that recognizes and binds a particular
amino acid (in this instance, phenylalanine). Which codon on the mRNA
strand codes for this amino acid?
A) UGG B) GUG C) GUA D) UUC E) CAU | |
front 46 - The tRNA shown in Figure 17.4 has its 3ʹ end projecting beyond
its 5ʹ end. What will occur at this 3ʹ end? A) The codon and
anticodon complement one another. B) The amino acid binds
covalently. C) The excess nucleotides (ACCA) will be cleaved off at
the ribosome. D) The small and large subunits of the ribosome will
attach to it. E) The 5ʹ cap of the mRNA will become covalently
bound.
| back 46 - B) The amino acid binds covalently.
|
front 47 - A mutant bacterial cell has a defective aminoacyl synthetase
that attaches a lysine to tRNAs with the anticodon AAA instead of a
phenylalanine. The consequence of this for the cell will be that
- A) none of the proteins in the cell will contain
phenylalanine.
- B) proteins in the cell will include
lysine instead of phenylalanine at amino acid positions
specified by the codon UUU.
- C) the cell will
compensate for the defect by attaching phenylalanine to tRNAs
with lysine-specifying anticodons.
- D) the ribosome
will skip a codon every time a UUU is encountered.
- E)
None of the above will occur; the cell will recognize the error
and destroy the tRNA.
| back 47 - B) proteins in the cell will include lysine instead of
phenylalanine at amino acid positions specified by the codon
UUU.
|
front 48 - There are 61 mRNA codons that specify an amino acid, but only
45 tRNAs. This is best explained by the fact that A) some tRNAs have
anticodons that recognize four or more different codons. B) the
rules for base pairing between the third base of a codon and tRNA
are flexible. C) many codons are never used, so the tRNAs that
recognize them are dispensable. D) the DNA codes for all 61 tRNAs
but some are then destroyed. E) competitive exclusion forces some
tRNAs to be destroyed by nucleases.
| back 48 - B) the rules for base pairing between the third base of a codon
and tRNA are flexible.
|
front 49 - What is the most abundant type of RNA? A) mRNA B) tRNA C) rRNA
D) pre-mRNA E) hnRNA
| |
front 50 - From the following list, which is the first event in
translation in eukaryotes? A) elongation of the polypeptide B) base
pairing of activated methionine-tRNA to AUG of the messenger RNA C)
the larger ribosomal subunit binds to smaller ribosomal subunits D)
covalent bonding between the first two amino acids E) the small
subunit of the ribosome recognizes and attaches to the 5ʹ cap of
mRNA
| back 50 - E) the small subunit of the ribosome recognizes and attaches to
the 5ʹ cap of mRNA
|
front 51 - Choose the answer that has these events of protein synthesis in
the proper sequence. 1. An aminoacyl-tRNA binds to the A site. 2. A
peptide bond forms between the new amino acid and a polypeptide
chain. 3. tRNA leaves the P site, and the P site remains vacant. 4.
A small ribosomal subunit binds with mRNA. 5. tRNA translocates to
the P site. A) 1, 3, 2, 4, 5 B) 4, 1, 2, 5, 3 C) 5,4,3,2,1 D) 4, 1,
3, 2, 5 E) 2, 4, 5, 1, 3
| |
front 52 - As a ribosome translocates along an mRNA molecule by one codon,
which of the following occurs? A) The tRNA that was in the A site
moves into the P site. B) The tRNA that was in the P site moves into
the A site. C) The tRNA that was in the A site moves to the E site
and is released. D) The tRNA that was in the A site departs from the
ribosome via a tunnel. E) The polypeptide enters the E site.
| back 52 - A) The tRNA that was in the A site moves into the P site.
|
front 53 - What are polyribosomes? A) groups of ribosomes reading a single
mRNA simultaneously B) ribosomes containing more than two subunits
C) multiple copies of ribosomes associated with giant chromosomes D)
aggregations of vesicles containing ribosomal RNA E) ribosomes
associated with more than one tRNA
| back 53 - A) groups of ribosomes reading a single mRNA
simultaneously
|
front 54 - Which of the following is a function of a signal peptide? A) to
direct an mRNA molecule into the cisternal space of the ER B) to
bind RNA polymerase to DNA and initiate transcription C) to
terminate translation of the messenger RNA D) to translocate
polypeptides across the ER membrane E) to signal the initiation of
transcription
| back 54 - D) to translocate polypeptides across the ER membrane
|
front 55 - When translating secretory or membrane proteins, ribosomes are
directed to the ER membrane by
- A) a specific
characteristic of the ribosome itself, which distinguishes free
ribosomes from bound ribosomes.
- B) a
signal-recognition particle that brings ribosomes to a receptor
protein in the ER membrane.
- C) moving through a
specialized channel of the nucleus.
- D) a chemical
signal given off by the ER.
- E) a signal sequence of
RNA that precedes the start codon of the message.
| back 55 - B) a signal-recognition particle that brings ribosomes to a
receptor protein in the ER membrane.
|
front 56 - When does translation begin in prokaryotic cells? A) after a
transcription initiation complex has been formed B) as soon as
transcription has begun C) after the 5ʹ caps are converted to mRNA
D) once the pre-mRNA has been converted to mRNA E) as soon as the
DNA introns are removed from the template
| back 56 - B) as soon as transcription has begun
|
front 57 - When a tRNA molecule is shown twisted into an L shape, the form
represented is A) its linear sequence. B) its 2-dimensional shape.
C) its 3-dimensional shape. D) its microscopic image.
| back 57 - C) its 3-dimensional shape.
|
front 58 An experimenter has altered the 3ʹ end of the tRNA corresponding to
the amino acid methionine in such a way as to remove the 3ʹ AC. Which
of the following hypotheses describes the most likely result?
A) tRNA will not form a cloverleaf. B) The nearby stem end
will pair improperly.
C) The amino acid methionine will not bind. D) The anticodon
will not bind with the mRNA codon.
E) The aminoacylsynthetase will not be formed. | back 58 C) The amino acid methionine will not bind. |
front 59 A transfer RNA (#1) attached to the amino acid lysine enters the
ribosome. The lysine binds to the growing polypeptide on the other
tRNA (#2) in the ribosome already.
- 59) Which enzyme causes a covalent bond to attach lysine to
the polypeptide? A) ATPase B) lysine synthetase C) RNA polymerase D)
ligase E) peptidyl transferase
| |
front 60 A transfer RNA (#1) attached to the amino acid lysine enters the
ribosome. The lysine binds to the growing polypeptide on the other
tRNA (#2) in the ribosome already.
- Where does tRNA #2 move to after this bonding of lysine to
the polypeptide? A) A site B) P site C) E site D) Exit tunnel E)
Directly to the cytosol
| |
front 61 - Which component of the complex described enters the exit
tunnel through the large subunit of the ribosome? A) tRNA with
attached lysine (#1) B) tRNA with polypeptide (#2) C) tRNA that no
longer has attached amino acid D) newly formed polypeptide E)
initiation and elongation factor
| back 61 - D) newly formed polypeptide
|
front 62 - The process of translation, whether in prokaryotes or
eukaryotes, requires tRNAs, amino acids, ribosomal subunits, and
which of the following? A) polypeptide factors plus ATP B)
polypeptide factors plus GTP C) polymerases plus GTP D) SRP plus
chaperones E) signal peptides plus release factor
| back 62 - B) polypeptide factors plus GTP
|
front 63 - When the ribosome reaches a stop codon on the mRNA, no
corresponding tRNA enters the A site. If the translation reaction
were to be experimentally stopped at this point, which of the
following would you be able to isolate? A) an assembled ribosome
with a polypeptide attached to the tRNA in the P site B) separated
ribosomal subunits, a polypeptide, and free tRNA C) an assembled
ribosome with a separated polypeptide D) separated ribosomal
subunits with a polypeptide attached to the tRNA E) a cell with
fewer ribosomes
| back 63 - A) an assembled ribosome with a polypeptide attached to the
tRNA in the P site
|
front 64 - Why might a point mutation in DNA make a difference in the
level of proteinʹs activity? A) It might result in a chromosomal
translocation. B) It might exchange one stop codon for another stop
codon. C) It might exchange one serine codon for a different serine
codon. D) It might substitute an amino acid in the active site. E)
It might substitute the N terminus of the polypeptide for the C
terminus.
| back 64 - D) It might substitute an amino acid in the active site.
|
front 65 - In the 1920s Muller discovered that X-rays caused mutation in
Drosophila. In a related series of experiments, in the 1940s,
Charlotte Auerbach discovered that chemicals she used nitrogen
mustardshave a similar effect. A new chemical food additive is
developed by a cereal manufacturer. Why do we test for its ability
to induce mutation? A) We worry that it might cause mutation in
cereal grain plants. B) We want to make sure that it does not emit
radiation. C) We want to be sure that it increases the rate of
mutation sufficiently. D) We want to prevent any increase in
mutation frequency. E) We worry about its ability to cause
infection.
| back 65 - D) We want to prevent any increase in mutation frequency.
|
front 66 - Which of the following types of mutation, resulting in an error
in the mRNA just after the AUG start of translation, is likely to
have the most serious effect on the polypeptide product? A) a
deletion of a codon B) a deletion of 2 nucleotides C) a substitution
of the third nucleotide in an ACC codon D) a substitution of the
first nucleotide of a GGG codon E) an insertion of a codon
| back 66 - B) a deletion of 2 nucleotides
|
front 67 - What is the effect of a nonsense mutation in a gene? A) It
changes an amino acid in the encoded protein. B) It has no effect on
the amino acid sequence of the encoded protein. C) It introduces a
premature stop codon into the mRNA. D) It alters the reading frame
of the mRNA. E) It prevents introns from being excised.
| back 67 - C) It introduces a premature stop codon into the mRNA.
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front 68 - Each of the following options is a modification of the sentence
THECATATETHERAT. Which of the following is analogous to a frameshift
mutation? A) THERATATETHECAT B) THETACATETHERAT C) THECATARETHERAT
D) THECATATTHERAT E) CATATETHERAT
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front 69 - Each of the following options is a modification of the sentence
THECATATETHERAT. Which of the following is analogous to a single
substitution mutation? A) THERATATETHECAT B) THETACATETHERAT C)
THECATARETHERAT D) THECATATTHERAT E) CATATETHERAT
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front 70 - Sickle-cell disease is probably the result of which kind of
mutation? A) point B) frameshift C) nonsense D) nondisjunction E)
both B and D
| back 70 - E) either an insertion or a deletion of a base.
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front 71 - A frameshift mutation could result from A) a base insertion
only. B) a base deletion only. C) a base substitution only. D)
deletion of three consecutive bases. E) either an insertion or a
deletion of a base.
| back 71 - E) either an insertion or a deletion of a base.
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front 72 - Which of the following DNA mutations is the most likely to be
damaging to the protein it specifies? A) a base-pair deletion B) a
codon substitution C) a substitution in the last base of a codon D)
a codon deletion E) a point mutation
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front 73 - Which point mutation would be most likely to have a
catastrophic effect on the functioning of a protein?
- A) a
base substitution
- B) a base deletion near the start
of a gene
- C) a base deletion near the end of the
coding sequence, but not in the terminator codon
- D)
deletion of three bases near the start of the coding sequence,
but not in the initiator codon
- E) a base insertion
near the end of the coding sequence, but not in the terminator
codon
| back 73 - B) a base deletion near the start of a gene
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front 74 - Which of the following statements are true about protein
synthesis in prokaryotes?
- A) Extensive RNA processing is
required before prokaryotic transcripts can be translated.
- B) Translation can begin while transcription is still in
progress.
- C) Prokaryotic cells have complicated
mechanisms for targeting proteins to the appropriate cellular
organelles.
- D) Translation requires antibiotic
activity.
- E) Unlike eukaryotes, prokaryotes require
no initiation or elongation factors.
| back 74 - B) Translation can begin while transcription is still in
progress.
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front 75 - Gene expression in Archaea differs from that in other
prokaryotes. It shares features with which of the following? A)
eubacteria only B) eukaryotes only C) protists only D) fungi only E)
bacteria and eukaryotes
| back 75 - E) bacteria and eukaryotes
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front 76 - Of the following, which is the most current description of a
gene?
- A) a unit of heredity that causes formation of a
phenotypic characteristic
- B) a DNA subunit that codes
for a single complete protein
- C) a DNA sequence that
is expressed to form a functional product: either RNA or
polypeptide
- D) a DNA—RNA sequence combination that
results in an enzymatic product
- E) a discrete unit of
hereditary information that consists of a sequence of amino
acids
| back 76 - C) a DNA sequence that is expressed to form a functional
product: either RNA or polypeptide
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front 77 - In eukaryotic cells, transcription cannot begin until A) the
two DNA strands have completely separated and exposed the promoter.
B) several transcription factors have bound to the promoter. C) the
5ʹ caps are removed from the mRNA. D) the DNA introns are removed
from the template. E) DNA nucleases have isolated the transcription
unit.
| back 77 - B) several transcription factors have bound to the
promoter.
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front 78 - Which of the following is not true of a codon? A) It consists
of three nucleotides. B) It may code for the same amino acid as
another codon. C) It never codes for more than one amino acid. D) It
extends from one end of a tRNA molecule. E) It is the basic unit of
the genetic code.
| back 78 - D) It extends from one end of a tRNA molecule.
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front 79 - The anticodon of a particular tRNA molecule is A)
complementary to the corresponding mRNA codon. B) complementary to
the corresponding triplet in rRNA. C) the part of tRNA that bonds to
a specific amino acid. D) changeable, depending on the amino acid
that attaches to the tRNA. E) catalytic, making the tRNA a
ribozyme.
| back 79 - A) complementary to the corresponding mRNA codon
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front 80 - Which of the following is not true of RNA processing?
-
A) Exons are cut out before mRNA leaves the nucleus.
-
B) Nucleotides may be added at both ends of the RNA.
-
C) Ribozymes may function in RNA splicing.
- D) RNA
splicing can be catalyzed by spliceosomes.
- E) A
primary transcript is often much longer than the final RNA
molecule that leaves the nucleus.
| back 80 - A) Exons are cut out before mRNA leaves the nucleus.
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front 81 - Using Figure 17.5, identify a 5ʹ → 3ʹ sequence of nucleotides
in the DNA template strand for an mRNA coding for the polypeptide
sequence Phe-Pro-Lys. A) 5ʹ-UUUGGGAAA-3ʹ B) 5ʹ-GAACCCCTT-3ʹ C)
5ʹ-AAAACCTTT-3ʹ D) 5ʹ-CTTCGGGAA-3ʹ E) 5ʹ-AAACCCUUU-3ʹ
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front 82 - Which of the following mutations would be most likely to have a
harmful effect on an organism?
- A) a base-pair substitution
- B) a deletion of three nucleotides near the middle of a
gene
- C) a single nucleotide deletion in the middle of
an intron
- D) a single nucleotide deletion near the
end of the coding sequence
- E) a single nucleotide
insertion downstream of, and close to, the start of the coding
sequence
| back 82 - E) a single nucleotide insertion downstream of, and close to,
the start of the coding sequence
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front 83 Which component is not directly involved in translation? | back 83 B) DNA
A) mRNA
B) DNA C) tRNA D) ribosomes
E) GTP |