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AP Bio Chapter Test Review

front 1

Which of the following statements correctly describes the normal tonicity conditions for typical plant and animal cells?

A. The animal cell is in an isotonic solution, and the plant cell is in a hypotonic solution

B. The animal cell is in an isotonic solution, and the plant cell is in a hypertonic solution

C. The animal cell is in a hypotonic solution, and the plant cell is in an isotonic cell

D. The animal cell is in a hypertonic solution, and the plant cell is in a hypotonic solution.

back 1

A, because all plant cells are hypertonic, and that means their environments are hypotonic.

front 2

The solutions in the two arms of this U-tube are separated by a membrane that is permeable to water and glucose but not to sucrose. Side A is half-filled with a solution of 2 M sucrose and 1 M glucose. Side B is half-filled with 1 M sucrose and 2 M glucose. Initially, the liquid levels on both sides are equal.

Initially, in terms of tonicity, the solution in side A with respect to that in side B is
A) hypotonic.
B) plasmolyzed.
C) isotonic.
D) saturated.
E) hypertonic.

back 2

C, because if you add both sides together, they are both 3 in terms of tonicity.

front 3

After the system reaches equilibrium, what changes are observed?
A) The molarity of sucrose and glucose are equal on both sides.
B) The molarity of glucose is higher in side A than in side B.
C) The water level is higher in side A than in side B.
D) The water level is unchanged.
E) The water level is higher in side B than in side A.

back 3

C, because glucose is permeable, so it will balance itself out. But since sucrose cannot move through the border, water will go into side A to reach equillibrium