front 1 Dispersion forces are mainly responsible for hydrogen bonding interactions. | back 1 False |
front 2 Temporary dipoles are mainly responsible for hydrogen bonding interactions. | back 2 False |
front 3 What is the main intermolecular force with the following compound? Three line zigzag with line off 2nd point. | back 3 Van der Waal |
front 4 What is the main intermolecular force with the following compound? Four line zigzag with NH2 coming off first point. | back 4 Hydrogen bonding |
front 5 What is the main intermolecular force with the following compound? Five line zigzag with Cl off 3rd point. | back 5 Dipole-dipole |
front 6 What is the main intermolecular force with the following compound? Zigzag with 6 lines. | back 6 Van der Waal |
front 7 Which compound has the lower boiling point? | back 7 4 line zigzag |
front 8 Which compound has the higher solubility in hexane (C6H14) ? | back 8 CH3CH2CH2CH2CH3 |
front 9 Which compound has the higher solubility in water? | back 9 4 line zigzag with Cl off 3rd point. |
front 10 Which compound has the lower boiling point? | back 10 5 line zigzag with O as 3rd point. |
front 11 Which compound has the higher boiling point? | back 11 Hexagon with N H at one of the vertices. |
front 12 Which compound has the lower boiling point? | back 12 4 line zigzag with N as 2nd point and another line coming off N. |
front 13 Which compound has the higher solubility in water? | back 13 5 line zigzag with N H as 3rd point. |
front 14 Which compound has the higher boiling point? | back 14 5 line zigzag with N H as 3rd point. |
front 15 An unknown liquid has a heat of vaporization of 6.14 kJ/mole. If the vapor pressure of this liquid at -196 degrees C is 90 torr, what is the normal boiling point of this liquid in degrees C? HINT: Normal boiling point occurs when the vapor pressure of the liquid is the same as atmospheric pressure (1 atm or 760 mm Hg). | back 15 P1 = 760 torr P2 = 90 torr T1 = ? T2 = -196 degrees C + 273 = 77 K delta H = 6.14 kJ/mole x (1000 J / 1 kJ) = 6,140 J/mole R = 8.314 K/J/mole ln (P2 / P1) = - (delta H / R) x (1/T2 - 1/T1) ln (90 / 760) = - (delta H / R) x (1/T2 - 1/T1) = 99 degrees C WRONG, ANSWER IS: -174 degrees C |
front 16 How much heat is released when 13.74 grams of a gas is cooled from a temperature of 120.7°C to a solid at -19.4°C? If the process is exothermic be sure to include the proper sign with your answer. Assume the molar mass of the sample is 21.95 grams/mole Melting point: 2.9°C Boiling point: 75.6°C Specific heat of the solid: 1.21 J/g°C Specific heat of liquid: 4.69 J/g°C Specific heat of gas: 1.28 J/g°C Enthalpy of fusion: 4.96 kJ/mol Enthalpy of vaporization: 21.84 kJ/mol Report your answer in kJ Do not type units with your answer. | back 16 NOT FINISHED BUT ANSWER SHOULD BE: -22.62 Moles of substance = mass / molar mass = 13.74 g / 21.95 g/mol = 0.625968 mol Q1 (solid, ice) = 13.74 g x 1.21 J/g°C x (2.9°C-(-19.4°C)) = Q2 (fusion, ice and water) = 4.96 kJ/mol x 0.625968 mol = kJ Q3 (liquid, water) = 13.74 g x 4.69 J/g°C x (75.6°C-2.9°C) = Q4 (vaporization, water and steam) = 21.84 kJ/mol x 0.625968 mol = kJ Q5 (gas, steam) = 13.74 g x 1.28 J/g°C x (120.7°C-75.6°C) = |
front 17 How much heat is released when 12.48 grams of a liquid is cooled from a temperature of 69.9°C to a solid at -10.4°C? If the process is exothermic be sure to include the proper sign with your answer. Assume the molar mass of the sample is 16.61 grams/mole Melting point: 3.9°C Boiling point: 99.7°C Specific heat of the solid: 1.25 J/g°C Specific heat of liquid: 2.22 J/g°C Specific heat of gas: 1.47 J/g°C Enthalpy of fusion: 5.10 kJ/mol Enthalpy of vaporization: 28.08 kJ/mol Report your answer in kJ Do not type units with your answer. | back 17 NOT FINISHED BUT ANSWER SHOULD BE: -5.88 |
front 18 Consider the phase diagram below: The critical pressure is: Screen reader description: The Ordinary Phases of Carbon Dioxide. Pressure (Pa) 10 to the power of 0 to 10 up to 10 to the power of 8 on Y-axis. Temperature in Kelvins 0 to 700 on X-axis. Curved line up from 105 K at 10 to the power of 0 Pa up to 200 K and 10 to the power of 6 Pa. The line forks here. There is an almost vertical line up to 10 to the power of 8 Pa, and a line that goes diagonally up and to the right to 325 K and 10 to the power of 7 Pa. To the left of the fork is "Solid". To the right of the fork is "Gas". In between the lines of the fork is "Liquid". End of image. | back 18 107 Pa |
front 19 Consider the phase diagram below: The pressure is increased slowly from 10 Pa at 200 K. Which of these best describes what is observed? Screen reader description: The Ordinary Phases of Carbon Dioxide. Pressure (Pa) 10 to the power of 0 to 10 up to 10 to the power of 8 on Y-axis. Temperature in Kelvins 0 to 700 on X-axis. Curved line up from 105 K at 10 to the power of 0 Pa up to 200 K and 10 to the power of 6 Pa. The line forks here. There is an almost vertical line up to 10 to the power of 8 Pa, and a line that goes diagonally up and to the right to 325 K and 10 to the power of 7 Pa. To the left of the fork is "Solid". To the right of the fork is "Gas". In between the lines of the fork is "Liquid". End of image. | back 19 It starts out as a gas, then becomes a solid. |
front 20 Consider the phase diagram below: What phase(s) is/are present at 10000000 Pa and 250 K? Screen reader description: The Ordinary Phases of Carbon Dioxide. Pressure (Pa) 10 to the power of 0 to 10 up to 10 to the power of 8 on Y-axis. Temperature in Kelvins 0 to 700 on X-axis. Curved line up from 105 K at 10 to the power of 0 Pa up to 200 K and 10 to the power of 6 Pa. The line forks here. There is an almost vertical line up to 10 to the power of 8 Pa, and a line that goes diagonally up and to the right to 325 K and 10 to the power of 7 Pa. To the left of the fork is "Solid". To the right of the fork is "Gas". In between the lines of the fork is "Liquid". End of image. | back 20 Liquid |
front 21 Consider the phase diagram below: What phase(s) is/are present at 100000 Pa and 300 K? Screen reader description: The Ordinary Phases of Carbon Dioxide. Pressure (Pa) 10 to the power of 0 to 10 up to 10 to the power of 8 on Y-axis. Temperature in Kelvins 0 to 700 on X-axis. Curved line up from 105 K at 10 to the power of 0 Pa up to 200 K and 10 to the power of 6 Pa. The line forks here. There is an almost vertical line up to 10 to the power of 8 Pa, and a line that goes diagonally up and to the right to 325 K and 10 to the power of 7 Pa. To the left of the fork is "Solid". To the right of the fork is "Gas". In between the lines of the fork is "Liquid". End of image. | back 21 Gas |