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  1. Print the notecards
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  1. Verify Front of pages is selected for Viewing and print the front of the notecards
  2. Select Back of pages for Viewing and print the back of the notecards
    NOTE: Since the back of the pages are printed in reverse order (last page is printed first), keep the pages in the same order as they were after Step 1. Also, be sure to feed the pages in the same direction as you did in Step 1.
  3. Cut out the notecards by cutting along each horizontal and vertical dotted line
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10 notecards = 3 pages (4 cards per page)

Viewing:

AP BIO ch 12 scenerio

front 1

How many of their daughters might be expected to be color-blind dwarfs?
A) all
B) none
C) half
D) one out of four
E) three out of four

back 1

none

front 2

What proportion of their sons would be color-blind and of normal height?
A) none
B) half
C) one out of four
D) three out of four
E) all

back 2

half

front 3

They have a daughter who is a dwarf with normal color vision. What is the probability that
she is heterozygous for both genes?
A) 0%
B) 25%
C) 50%
D) 75%
E) 100%

back 3

100%

front 4

Between which two genes would you expect the highest frequency of recombination?
A) A and W
B) W and E
C) E and G
D) A and E
E) A and G

back 4

A and G

front 5

In a series of mapping experiments, the recombination frequencies for four different linked
genes of Drosophila were determined as shown in Figure 12.2. What is the order of these genes
on a chromosome map?
A) rb-cn-vg-b
B) vg-b-rb-cn
C) cn-rb-b-vg
D) b-rb-cn-vg
E) vg-cn-b-rb

back 5

b-rb-cn-vg

front 6

A plantlike organism on the planet Pandora can have three recessive genetic traits: bluish leaves,
due to an allele (a) of gene A; a feathered stem, due to an allele (b) of gene B; and hollow roots
due to an allele (c) of gene C. The three genes are linked and recombine as follows:
A geneticist did a testcross with an organism that had been found to be heterozygous for the
three recessive traits and she was able to identify progeny of the following phenotypic
distribution (+ = wild type):

Which of the following are the phenotypes of the parents in this cross?
A) 2 and 5
B) 1 and 6
C) 4 and 8
D) 3 and 7
E) 1 and 2

back 6

4 and 8

front 7

In which progeny phenotypes has there been recombination between genes A and B?
A) 1, 2, 5, and 6
B) 1, 3, 6, and 7
C) 2, 4, 5, and 8
D) 2, 3, 5, and 7
E) in all 8 of them

back 7

1, 2, 5, and 6

front 8

If recombination frequency is equal to distance in map units, what is the approximate distance
between genes A and B?
A) 1.5 map units
B) 3 map units
C) 6 map units
D) 15 map units
E) 30 map units

back 8

3 map units

front 9

What is the greatest benefit of having used a testcross for this experiment?
A) The homozygous recessive parents are obvious to the naked eye.
B) The homozygous parents are the only ones whose crossovers make a difference.
C) Progeny can be scored by their phenotypes alone.
D) All of the progeny will be heterozygous.
E) The homozygous recessive parents will be unable to cross over.

back 9

Progeny can be scored by their phenotypes alone.

front 10

The greatest distance among the three genes is between a and c. What does this mean?
A) Gene c is between a and b.
B) Genes are in the order: a–b–c.
C) Gene a is not recombining with c.
D) Gene a is between b and c.
E) Distance a–b is equal to distance a–c.

back 10

Genes are in the order: a–b–c.