CHEM 23: Stoichiometric Calculations: The Workhorse of the Analyst Flashcards


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UP Cebu - Chem 23 Stoichiometric Calculations: The Workhorse of the Analyst
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1

stoichiometry

the ratios in which chemicals react, from which we apply appropriate conversion factors to arrive at the desired calculated results

2

definition of avogadro's number

tells the number of particles in 1 mole (or mol) of a substance.

3

avogadro's number

6.022x1023

4

atomic weight

is the weight of a specified no. of atoms in that element

5

molecular weight

the sum of the atomic weights of the atoms that make up a compound

6

Find the molecular weight of HCl

(1.0080)+(35.45) = 36.458 g/mol (insert surname)

7

formula weight

sum of atomic weights but for ionic compounds

8

Find the formula weight of NaOH

(22.990) + (12.011) + (1.0080) = 40 g/mol (insert surname)

9

equivalent weight

the mass of one equivalent, that is the mass of a given substance which will combine with or displace a fixed quantity of another substance

10

formula of equivalent weight

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11

percent by mass

is the ratio of the mass of a solute to the mass of the solution multiplied by 100 percent

12

formula of percent by mass

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13

A sample of 0.894 grams (g) of potassium chloride (KCl) is dissolved in 54.8 grams of water. What is the percent by mass of KCl in the solution?

1.61%

14

percent by volume

a unit of concentration used to express the amount of solute in a solution as a percentage of the volume of the solution.

15

formula of percent by volume

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16

In a solution, there is 122.4 mL solvent and 5.24 ml solute present. Find the percent by volume.

4.11%

17

mole

amount or sample of a chemical substance that contains as many constitutive particles as there are atoms in 12 grams = carbon – 12 (12g C-12 = 1mol)

18

formula of mole

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19

molarity

one-molar solution is defined as one that contains one mole of substance in each liter of solution

20

formula of molarity

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21

normality

one normal solution contains one equivalent per liter

22

formula of normality

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23

dilution

for preparation of a smaller concentration

24

formula of dilution

C1V1=C2V2

25

parts per million

represents the number of parts of a substance per million parts of the solution

26

formula of parts per million

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27

A solution has a concentration of 1.24 g/L. What is its concentration in ppm?

1240 ppm