q = m Cs △T
△T = Tf - Ti
△T = 43.6°C - 24.5°C = 19.1°C
q = (47.50 g) x (4.184 J/g°C) x (19.1°C)
q = 3,795.9 J
A metal sample weighing 121.00 grams and at a temperature of 98.6 degrees Celsius was placed in 42.00 grams of water in a calorimeter at 24.0 degrees Celsius. At equilibrium the temperature of the water and metal was 35.2 degrees Celsius.
What is the change in temperature of the water (in degrees C)? (Report this as a positive value)
A metal sample weighing 126.00 grams and at a temperature of 96.9 degrees Celsius was placed in 48.00 grams of water in a calorimeter at 22.0 degrees Celsius. At equilibrium the temperature of the water and metal was 38.4 degrees Celsius.
What is the change in temperature of the metal (in degrees C)? (Report this as a positive value)
A metal sample weighing 130.00 grams and at a temperature of 96.5 degrees Celsius was placed in 47.50 grams of water in a calorimeter at 24.5 degrees Celsius. At equilibrium the temperature of the water and metal was 43.6 degrees Celsius.
How much heat flowed into the water? (Report your answer in J)
The specific heat of the water is 4.184 J/g/C
Report your answer to three significant figures. The value should be positive.
DO NOT USE EXPONENTIAL NOTATION